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Need help with a physics force problem?
Two boxes, a mass 4.00 and the other with a mass of 6.00, sit on the smooth surface a frozen pond, connected by a light rope (Intro 1 figure). A women's golf shoes (so they get traction on the ice) moves horizontally on the 6.00 box of a force that the crate is an acceleration of 2.90. Use to find the Newton's second law, the tension in the rope that connects the two boxes.
You should start box by the forces on both. The box of mass 4 has the following forces: the normal force of gravity down to the top (these two cancel) Voltage in the rope pulls him to the right of the box mass 6 has the following forces: the normal force of gravity down to the top (these two) abolish tension in the rope, it moves to the left of the woman pulls him to the right so we have the following equations. For box of mass 4: T = m * a for the cases of mass 6: F = (Woman's pulling force) F – T = m * a The acceleration of the two blocks should be 2.90, as they move as a single body. So, T = m * a is the only equation that we really need. T = 4.00 * 2.90 T = 11.6
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